Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in standard form. 4, -2, and -1 + 2i
f(x) = x4 - 3x3 + 8x2 + 13x + 40 correct
start with \[(x-4)(x+2)(x-(-1+2i))(x-(1-2i))\] and multiply out but before we being the last product is very easy
can you kinda go back words with me work best that way please and thanks
if the zeros are \(a+bi\) and \(a-bi\) the quadratic is \[x^2-2ax+(a^2+b^2)\] in your case it is \[x^2+2x+5\]
ok lets start at the very beginning
if \(-1+2i\) is a zero, then so is its conjugate \(-1-2i\)
the quadratic equation that will have those two zeros is \[x^2+2x+5\] is it clear how i got that?
rightt i got that
oh ok good then your final job is to multiply out \[(x-4)(x+2)(x^2+2x+5)\]
f(x) = x4 - 7x2 - 26x - 40
you can do it in any order you like , but as you can see it is a bunch of algebra you have to do. yes, that is correct
thankkkksss
yw, it looks like you did it on your own good job
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