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Mathematics 5 Online
OpenStudy (anonymous):

Factor the following four-term polynomial by grouping. x^3+5x^2+x+5

OpenStudy (mathstudent55):

See what you can factor from first two terms, then see what you can factor from last two terms.

OpenStudy (mathstudent55):

What common factor is there in x^3 + 5x^2?

OpenStudy (anonymous):

\[k \ge 5;0\]

OpenStudy (anonymous):

x^3?

OpenStudy (mathstudent55):

No, because there is no x^3 in the second term. It's only x^2. Now factor that x^2 from first two terms: x^3 + 5x^2 + x + 5 = x^2(x + 5) + x + 5 Now since there is nothing that can be factored out of the last two terms, x + 5, you can always say you can factor 1, so do ti: x^2(x + 5) + 1(x + 5) Now you have the same factor of x + 5 in the first part and in the second part, so factor out x + 5: (x + 5)(x^2 + 1)

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