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can someone simplify this for me
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\[\cos ^{2}\theta(\sec ^{2}\theta-1)\]
sec^2 = 1/cos^2
cos^2θ(sec^2θ−1) cos^2θ(1/cos^2θ−1) (cos^2θ/cos^2θ-cos^2θ) (1-cos^2θ) sin^2θ
so its sin^2(theta)? since the answer is 1-cos^2(theta)
okay thanks
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the identity sin^2 + cos^2 = 1 sin^2 = 1 -cos^2
what about cosx/1+tan^2x ?
i dont knwo what to do after i change the tan^2 to sin^2x/cos^2x
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