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Mathematics 19 Online
OpenStudy (anonymous):

can someone simplify this for me

OpenStudy (anonymous):

\[\cos ^{2}\theta(\sec ^{2}\theta-1)\]

OpenStudy (anonymous):

sec^2 = 1/cos^2

OpenStudy (anonymous):

cos^2θ(sec^2θ−1) cos^2θ(1/cos^2θ−1) (cos^2θ/cos^2θ-cos^2θ) (1-cos^2θ) sin^2θ

OpenStudy (anonymous):

so its sin^2(theta)? since the answer is 1-cos^2(theta)

OpenStudy (anonymous):

okay thanks

OpenStudy (anonymous):

the identity sin^2 + cos^2 = 1 sin^2 = 1 -cos^2

OpenStudy (anonymous):

what about cosx/1+tan^2x ?

OpenStudy (anonymous):

i dont knwo what to do after i change the tan^2 to sin^2x/cos^2x

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