Question

derivative of y=(-4x)/y , can anyone help me?

Answer 1

\[\frac{ -4x }{ y }-y = 0 \rightarrow -4x(y)^{-1}-y=0 \rightarrow 4xy ^{-2} \frac{ dy }{ dx }-4y ^{-1}-\frac{ dy }{ dx }\]

Answer 2

\[\frac{ dy }{ dx }(\frac{ 4x }{ y ^{2} }-1) = -\frac{ 4 }{ y } \rightarrow \frac{ \frac{ 4 }{ y } }{ \frac{ 4x }{ y ^{2}-1 } } = \frac{ dy }{ dx } = \frac{ (y ^{2}-1) }{ xy }\]

Answer 3

hopefully this is correct, it's been a while since I've done implicit differentiation.

Answer 4

thnx

Answer 5

nope unfortunately there is nothing like this int he answers

Answer 6

maybe instead of using the quotient rule, it would be easiest to start with
\[y^2=-4x\] so you get
\[2yy'=-4\] or \[y'=-\frac{2}{y}\]

Answer 7

actually this is the second derivative started with
4x^2+y^2=9

Answer 8

because the results here are not even close to what I have on the sheet

Answer 9

found it!!!
-(4x^2+16y^2)/y^3

Answer 10

thanks anyway