Question

solve tan^2x-3=0??

Answer 1

u mean tan(2x-3) ?

Answer 2

no tan^2(x)-3=0
=)

Answer 3

tan^2 (2x-3) ?

Answer 4

uhh tan square x -3 = 0

Answer 5

try tan^2 = sin^2 +cos^2
sin^2 x =(1-cos2x)/2 ; cos^2 x = (1+cos2x)/2

Answer 6

but how do i use that to solve for x?

Answer 7

the numerator gotta be 0, denominator cannot

Answer 8

sorry but i'm more lost now =( but in the previous problem it said to solve 2 cosx -1 = 0 and i got x = [(2π)/3]+2πn and x = [(4π)/3] +2πn where n is any interger

Answer 9

because you dont have interval to limit, so it's the value plus any# of revolution of circle

Answer 10

so one of the answers would be x = (π/3)+πn right?

Answer 11

One of the answer in which problem?

Answer 12

tan square x -3 = 0

Answer 13

\[\tan ^{2}x-3=0\]

Answer 14

cos(2x-3) =1, 2x-3 =0 or 2pi, x=?

Answer 15

idk =/ i think i'll skip it but thanx anyway ^_^