Question

Please help crashing for finals!
The length of the rectangle is 4t+5 and its height is t^6, where t is time in seconds and the dimensions are in inches. Find the rate of change of area, A, with respect to time.

Answer 1

A= l*h = (4t+5)(t^6)

dA/dt = d/dt (4t^7 +5t^6 )

Answer 2

my teacher gave me the answer it is dA/dt=t^3(30+28t) but im not so sure as to how to do the problem

Answer 3

aka
28t^6 +30t^5

Answer 4

thats what i got when i first did the problem what you gave me just now

Answer 5

dA/dt=t^5(30+28t)

think you have a typo there..

Answer 6

or in the original problem...

Answer 7

yeah you know what i was thinking that too. so doing the problem just as i had done it taking the derivative of the problem thats how we go about these problems right? simply taking the derivative??

Answer 8

sure

Answer 9

:( no i need a definite answer because i have a final in a couple of days and i NEED to get a good score on it

Answer 10

"so doing the problem just as i had done it taking the derivative of the problem thats how we go about these problems right?"

I have no idea what that word salad might mean... so I decline to comment on it aside from a provisional 'sure'

Answer 11

okay then thanks