Factor the following four-term polynomial by grouping. x^3+3x^2+x+3

Question

anonymous · Answer

$$x^2(x+3)+(x+3)$$ is the first step

anonymous · Answer

second step is $(x^2+1)(x+3)$

anonymous · Answer

don't understand..

anonymous · Answer

ok did you understand the first step of taking the $x^2$ and factoring it out of the first two terms?

anonymous · Answer

Yes got that

anonymous · Answer

ok so we have two terms, the first one is $x^2(x+3)$ and the second one is $x+3$

anonymous · Answer

we can visualize it as 
$$x^2(x+3)+1(x+3)$$

anonymous · Answer

now there are two terms, and both have a common factor of $x+3$ 
the first time is $x+3$ times $x^2$ and the second term is $x+3$ times $1$

anonymous · Answer

so we can factor out the $x+3$ from both terms and see that you have 
$$(x+3)(x^2+1)$$

anonymous · Answer

it's so confusing but so far little by little i got it thank you @satellite73

anonymous · Answer

i'm getting it*