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Chemistry 19 Online
OpenStudy (anonymous):

HEELP ME PLEASE! Balance the chemical equations. a) KOH(aq) + H2SO4(aq) -> K2SOa(aq)

OpenStudy (anonymous):

what is K2SOa...K2SO4?...and why are there no Hs on the product side..or is that part of the problem?

OpenStudy (anonymous):

the numbers are suppose to be lower case but i don't know how to put that in here...

OpenStudy (anonymous):

\[4KOH+2H _{2}SO _{4}--->2K _{2}SO _{4} +8H ^{+}\]

OpenStudy (anonymous):

May I ask how you did that? ):

OpenStudy (anonymous):

So, as a rule of thumb balance H's last I tried to balance the K's first. I noticed that the products had twice as many as the reactants, so i knew that koh had to be double k2so4. Next i tried to balance the O's

OpenStudy (anonymous):

Seeing that i had too many on the reactants side, i doubled the only o's on the products. But wait doubling this changed the K's...so i then had to change the k in the reactant side to 4. Lastly i just counted the h's and balance them

OpenStudy (anonymous):

Ooooh alright, thank you! :)

OpenStudy (anonymous):

no problem..sorry its a little hard to explain

OpenStudy (anonymous):

\[KOH (aq) + H2SO4 (aq) -> K2SO4 (aq) + H2O\]

OpenStudy (anonymous):

your k's arent balanced in the last post

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