Question

Find the area of the region bounded by the graph of the equation.
y = 3x^2 +1; x=0, x= 8, y =0

Answer 1

integrate y from 0 to 8

Answer 2

what's the y for then?

Answer 3

y = f(x)

\[\int_{a}^{b}f(x)~dx\]

Answer 4

i spose if you wanted to subtract the bottom y function from
the top y function .... but f(x)-0=f(x)

Answer 5

in general, the area between 2 curves; say f(x) and g(x) is:\[\int_{a}^{b}f(x)-g(x)~dx\]

Answer 6

its ok, i know how to find the area.

Answer 7

i knew you did :)

Answer 8

sorry, for another question. y = x^3+x, and x=2, and y = 0
how would i do that?

Answer 9

those the "bounds"?

Answer 10

oh wait i think i know what it means. sorry.