√x-1 -x= -1 ( what is x??)

Question

√x-1   -x= -1 ( what is x??)

anonymous · Answer

$$\sqrt{x-1}= x-1$$R u there? I can show you how to do this

anonymous · Answer

yes!!! im here!!!

anonymous · Answer

Ok so first you have to get the radical by itself which i did by adding x to each side of teh equation

anonymous · Answer

Now we have to square both sides to get rid of the radical

anonymous · Answer

$$x-1=(x-1)(x-1)$$Careful because you have to FOIL the right side

anonymous · Answer

$$x-1=x^2-2x+1$$

anonymous · Answer

Now set the equation equal to zero.

anonymous · Answer

sure....
yes!!!

anonymous · Answer

X^2-x +2

anonymous · Answer

$$0=x^2-3x+2$$You can either factor this and solve for x or use the quadratic

anonymous · Answer

Right???
In algebra 2, were learning how to factor radicals....teach me how to do that!!!

anonymous · Answer

$$0=(x-2)(x-1)$$$$x=2,1$$Here's the last step. Now I'll teach you how to do it

anonymous · Answer

k

anonymous · Answer

|dw:1355197265419:dw|

Right??? Thank you!!! You've been a great help.

anonymous · Answer

$$x^2-3x+2$$So lets factor this. You want to break up the middle term into 2 numbers that add to the middle term(-2-1=-3) Also these numbers when multiplied should equal the last term(-2*-1=2).$$x^2-2x-x+2$$Now we are going to group them$$(x^2-2x)+(-x+2)$$Now we have oto do some small factoring$$x(x-2)+-1(x-2)$$x is in each term so I factored that out. I wanted a positive x so i factored out -1 from the other term. Now we have a (x-2) in each term so we are actually going to factor this out.$$(x-2)(x-1)$$Done. Questions?

anonymous · Answer

correct to ur previous comment

anonymous · Answer

k

anonymous · Answer

Did you understand the factoring? Eventually you'll get good and recognize patterns and not have to do any of that