Help can't solve!!!

A company that conducts bus tours found that when the price was $9.00 per person, the average number of customers was 1000 per week. When the company reduced the price to $7.00 per person, the average number of customers increased to 1500 per week. Assuming that the demand function is linear, what price should be charged to obtain the greatest weekly revenue? Revenue is price times number sold. Also fine the maximum revenue.

Question

Help can't solve!!!

A company that conducts bus tours found that when the price was $9.00 per person, the average number of customers was 1000 per week. When the company reduced the price to $7.00 per person, the average number of customers increased to 1500 per week. Assuming that the demand function is linear, what price should be charged to obtain the greatest weekly revenue? Revenue is price times number sold. Also fine the maximum revenue.

anonymous · Answer

i got $5.00 and the maximum revenue $10,000

anonymous · Answer

Okay can you explain to me how you got that. :)

anonymous · Answer

That can't be right b/c 7 times 1500 is 10,500

anonymous · Answer

because if you have $9.00 tickets x 1000 customers=$9000 then if you have $7.00 x 1500 customers=$7500 if you lower it down to $5.00 per ticket, you get 2000 customers because the amount of customers is increasing by 500 every $2.00 dropped from the ticket price. so $5.00x2000=$10000 ........oops sorry its $7.00 and 1500 customers. and your max revenue is $10,500 you cant go any lower or you drop in revenue!

anonymous · Answer

Okay thanks :)

anonymous · Answer

yeah

anonymous · Answer

Okay did you solve this using calculus or algebra? Because this is a calculus math problem, you do know that right?