Mathematics
12 Online
OpenStudy (666potatoes):
Rationalize the denominator:
√5 / (√5 + 2)
[2 is not part of the square root of 5]
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OpenStudy (anonymous):
multiply both sides by \[\sqrt{5} - 2\]
OpenStudy (anonymous):
rachel is right, multiply by the reciprocal
OpenStudy (666potatoes):
Would it leave me with √25 - 2 ?
OpenStudy (666potatoes):
Or √25 - 2 / √25 - 4 ?
OpenStudy (anonymous):
the radicals cancel
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OpenStudy (666potatoes):
Ah that's what I thought. So it is just √25 - 2 ? so it would be 3?
OpenStudy (anonymous):
\[25-2\sqrt{5}\]
OpenStudy (anonymous):
(You had to multiply root 5 by -2)
OpenStudy (anonymous):
how do you get 25-2root5...i got 5-2root5..
OpenStudy (666potatoes):
Zomg, a dispute.
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OpenStudy (666potatoes):
I don't think the radicals cancel out when multiplying √5 by √5 in the numerator. :l
OpenStudy (666potatoes):
But then that means the denominator radicals wouldn't cancel out so weogheoiwghoiew.
OpenStudy (anonymous):
They do! if you multiply the same radicals together they drop the radical sign
OpenStudy (666potatoes):
Alright, I'm going with Rachel's answer. Haha.
OpenStudy (anonymous):
i agree with rachel, i just get the 25...cuz in the numerator i was getting root 5 times root5 -2. root 5 times root 5 =5 not 25
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OpenStudy (anonymous):
just not*
OpenStudy (anonymous):
Oh right. sorry i messed up.
OpenStudy (anonymous):
haha its cool..i wrote that at first too
OpenStudy (anonymous):
all rightie! good luck with math, and finals if you have them!
OpenStudy (666potatoes):
So the correct answer is 5-2√5. Right?
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OpenStudy (anonymous):
Yep!
OpenStudy (666potatoes):
Ty gaiz. c: