Question

Write and Solve Partial Fraction Decomposition of a Rational Expression (LOOK IN FOR EQUATION)

Answer 1

\[\frac{ 2x }{ x ^{3}-1 }\]

Answer 2

how did you get your first step?

Answer 3

\[x^3-1=(x-1)(x^2+x+1)\]

Answer 4

so

\[\frac{2x}{x^3-1}=\frac A{x-1}+\frac {Bx+C}{x^2+x+1}\]

Answer 5

the factor (x^2+x+1) is quadratic , so the denominator must be linear, not just a scalar

Answer 6

pardon?

Answer 7

in where?

Answer 8

im not sure what you are saying

Answer 9

from the start.

Answer 10

\[\frac{2x}{x^3-1}=\frac{2x}{(x-1)(x^2+x+1)}=\frac A{x-1}+\frac {Bx+C}{x^2+x+1}\]

\[2x=A(x^2+x+1)+(Bx+C)(x-1)\]

to find the constants try x=1 , x=0

Answer 11

Is This Correct?
b=-2/3
c=2
a=2/3

Answer 12

\[\color{red}\checkmark\]great work