Question

Can someone check my work?

Answer 1

12ab+4b+2a+6
12ab+4b+2a+6
(12ab+4b)+(2a+6)
4b(8a+1)+6(2a+1)
(2a+1)(4b+6)

Answer 2

Factoring by Grouping (four-term polynomials and trinomials)

Answer 3

That's not correct because notice how 2a times 4b = 8ab, which is not 12ab

Answer 4

oh..How do I correct it then?

Answer 5

is 12ab+4b+2a+6 the original problem?

Answer 6

well I had to provide an example for [Factoring by Grouping] (four-term polynomials and trinomials) so that was what I came up with lol.

Answer 7

oh so it was completely random?

Answer 8

yes

Answer 9

try starting with something factored, and expanding it out

Answer 10

like (a+2b)(a-3b)

Answer 11

im a little confused

Answer 12

expand out (a+2b)(a-3b)

Answer 13

wait how do I do that. Maybe I misunderstood everything in my lesson, cause I dont know how I would do that

Answer 14

Couldnt I just replace the 12ab in my orignal problem with 8? and change whatever else would need to be changed?

Answer 15

you can change the 2a to 6 and the 6 to 2 to get

12ab+4b+6a+2

now try

Answer 16

ok. so I get 12ab+4b+6a+2
then I do this (12ab+4b)+(6a+2)?

Answer 17

yes keep going

Answer 18

and then im stuck on the next part i think. it would be 4b(8a+1)+2(6a+1)?

Answer 19

no, factor 4b from the first group to get 4b(3a + 1)

Answer 20

factor 2 from the second to get 2(3a + 1)

Answer 21

ok. so then it would be 4b(3a+1)+2(3a+1)?

Answer 22

yep, then factor out 3a+1

Answer 23

what would that look like? 3?

Answer 24

what do you mean by 3

Answer 25

just factor out 3a+1 to get (4b+2)(3a+1)

Answer 26

ok thats what I thought, but I was not sure...so I second guessed myself.

Answer 27

thankyou

Answer 28

np