Find the acute angle between the lines: y=2x+4 and y=-3x+6
the angle, theta, between lines with known slopes, m1 and m2, is given by the relation: \(\huge tan\theta=\frac{m_2-m_1}{1+m_1m_2} \)
So I would do the inverse tan of that?
do you mind to explain how the formula is arrived at?
yep...
Thanks.
ok... do you know about inclination??
rise over run?
no... inclination is an ANGLE a line makes with the positive x axis....
yes, so that is tan-1(rise/run)
if in first quadrant
it doesn't matter if it's in the first quadrant or not.... the inclination is just the angle it makes with the positive x axis at the point where the line intesects the x axis:|dw:1355204236495:dw|
on my calc i was getting negative answers that i had to change around...
so to get the angle between two lines, you're basically subtracting the inclination of the two lines....
oh yeah.... sorry, my bad.... the actual formula is: \(\large tan\theta=|\frac{m_2-m_1}{1+m_2m_1}| \)
thankyou!
|dw:1355204493130:dw| the angle between the two lines is alpha and you can just use angle sum formula for tangent.
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