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Mathematics 15 Online
OpenStudy (anonymous):

Let f(x)=(5x2+5x+5)^.5 f'(x)

OpenStudy (anonymous):

are you looking for the derivative?

OpenStudy (anonymous):

yes f prime of x

OpenStudy (anonymous):

You will have to use the chain rule for this (.5*(g(x))^(-.5))*g'(x)

OpenStudy (anonymous):

g(x) equals the function inside the paranthesis

OpenStudy (anonymous):

f(x) =(5x^2+5x+5)^.5

OpenStudy (anonymous):

okay so that is 5x^2+5x+5

OpenStudy (anonymous):

yeah g(x) =5x^2+5x+5, now apply the chain rule like I showed above If you need any help let me know

OpenStudy (anonymous):

okay im going to try again thanks so far

OpenStudy (anonymous):

i keep getting this one wrong i need further assistance if it isn't to much trouble i got .5(5x^2+5x+5)^-.5+(5x^2+5x+5)^.5(5x+5)

OpenStudy (raden):

it should be f' = (1/2) * (10x+5)/sqrt(5x^2+5x+5)

OpenStudy (anonymous):

lol smh i forgot to do one of the derivative several times. thx

OpenStudy (raden):

yw

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