Question

Find the anti-derivative of xsqrtx+1 using substitution
show steps

Answer 1

are u sure its
\(f(x)=x\sqrt x+1\)
?

Answer 2

\[x \sqrt{x+1}\]

Answer 3

ok, then
put x+1 = u
find du=.. ?

Answer 4

du=((x^2)/2)+x
?

Answer 5

x+1 = u
taking deribative
dx+0 = du
so,
dx is just du.

Answer 6

oooo I was doing the anti derivative for du. ok thanks

Answer 7

hmm....so could you solove further ?

Answer 8

so now the equation is sqrtu du
?

Answer 9

\(\sqrt{x+1} = \sqrt u \\ x=u-1 \\dx=du\)
so whats your new integral ?

Answer 10

u-1sqrtu du

Answer 11

yes, now thats an easy integral t solve
can u ?

Answer 12

yea I got this thanks

Answer 13

welcome ^_^