Question

Six boys and six Girls sit in a row . The probability that all girls sit together

Answer 1

find the total number of arrangement with girls together.

Answer 2

Arrangment = 6!*6!

Answer 3

find the total number of arrangement.

Answer 4

is this correct

Answer 5

518400

Answer 6

12!
the probability = 6!6!/12!

Answer 7

actually, it will be easier if we use the complementary of probability
P(A) = 1-P(A')
let P(A') is event of all girls sit by alternate

Answer 8

so, P(A) = 1 - (2*6!6!/12!)

Answer 9

am i wrong @experimentX ?

Answer 10

no. of ways in which all girls sit together = 7! * 6!
and total no. of ways of seating of 12 people = 12 !
so probability = 7! 6! / 12!

Answer 11

why you guys taking 6! 6! ?

Answer 12

hw 7....?

Answer 13

if me,
case I : B-G-B-G-B-G-B-G-B-G-B-G
case II : G-B-G-B-G-B-G-B-G-B-G-B
but, i have used the complement of probability

Answer 14

lets consider all 6 girls as one,,
so we have 7 people => 6 boys and 1 girl.. => 7!
also,,6 girls can change in 6! ways, so final arrangement= 7! * 6!

Answer 15

that's why i multiplied by 2

Answer 16

@RadEn your case will also involve something like

B-GG-B-GG-B-G-B-G-BB and etc..

Answer 17

woops!! it's 7!

Answer 18

but, B-GG-B-GG-B-G-B-G-BB is not alternate way

Answer 19

if you subtract from 1 the probability that no 2 girls sit together,, that doesnt mean that all girls will sit together,,maybe am not able to explain well..anyone can help ?

Answer 20

maybe,, i was also wrong in translating that problem :)