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For the given statement Pn, write the statements P1, Pk, and Pk+1.
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whats up with the 3.2 ?
woops sorry. just 2. no 3.
2 + 4 + 8 + . . . + 2n = 2^(n+1) - 2
@satellite73
@amistre64 @badi @Callisto @experimentX @Hero @phi @.Sam.
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P(1) replace \(n\) by \(1\)
can you show me how to work this out.
@phi
if you put \(n=1\) you get \(2=2^{1+1}-2\)
where i saw an \(n\) i replaced it by \(1\) this is clearly true, since \[2=2^2-2=4-2=2\] is true
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\(P_k\) is also a replacement, replace \(n\) by \(k\) i.e write exactly what you see with \(k\) instead of \(n\)
\[P(n):2 + 4 + 8 + . . . + 2n = 2^{n+1} - 2\] \[P(k):2 + 4 + 8 + . . . + 2k = 2^{k+1} - 2\]
and for \(P(k+1)\) replace \(n\) by \(k+1\)
ty :)
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