Question

Bet no one can solve this one:

Find the inverse laplace transform of log ((S^2+1)/(S^2))

Answer 1

its easy

Answer 2

Can you show me then? o-O

Answer 3

do u know
\(L[any function]= -1/t L[derivative of given function]\)
??

Answer 4

sorry, those are inverse Laplace.

Answer 5

\(L^{-1}[F(s)]= -1/t \quad L^{-1}[d/dt {F(s)}]\)
did u know this ?

Answer 6

\(L^{-1}[log ((S^2+1)/(S^2))]= -1/t \quad L^{-1}[d/dt[ {log ((S^2+1)/(S^2))]}]\)

Answer 7

that should be d/ds
so what is
d/ds [log ((S^2+1)/(S^2))]

Answer 8

Ahh I see. Thank you very much. I can do the rest from here. :)

Answer 9

also verify your question...is it correct ? ot is there any square root sign ?

Answer 10

hmm.. ok
welcome ^_^