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Physics 6 Online
OpenStudy (anonymous):

If you throw a ball upwards from a building at x velocity, when it's coming back down and is at a point that it has the same height as it did initially; is the v the same? I don't know i'm having conceptual problems; here's a question i had a problem with: Ball A is thrown vertically upward with a speed of 19.6 m/s from the top edge of a high building. As it passes the edge on the way down, a second ball, B, is thrown downward at 19.6 m/s. Which of the following is correct? Ball A hits the ground before B. The two balls hit the ground at the same time. Ball B hits the ground before A.

OpenStudy (anonymous):

When you through a ball up it follows a parabolic curve. So for the first one the magnitude of v will be the same as when you first threw it. The only difference is that the velocity is now negative. The balls will hit at the same time

OpenStudy (anonymous):

does that make sense?

OpenStudy (anonymous):

3rd option is correct,beacause ball A should have to cover two paths, one is upward and the second is downward so A ball reaches next to ball B

OpenStudy (anonymous):

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