Question

Three resistors are connected in parallel in a circuit with a 9-volt battery. The resistors are 4, 6 and 12 ohms. Calculate the current in the circuit.

Answer 1

@supercrazy92 can u help?

Answer 2

Do you know how to calculate the resistance in parallel combination ?

Answer 3

well i added them and i got 22 and i divided by 9 but i dont know if i got it right

Answer 4

the answer choices are these
A 18 amps
B. 9 amps
C. 4.5 amps
D. 2.25 amps

Answer 5

For parallel combination

\[\frac{ 1 }{ R } = \frac{ 1 }{ R_1 } + \frac{ 1 }{ R_2 } + \frac{ 1 }{ R_1 }\]

Solve this , you'll get the Total resistance

after that , use Ohm's law again to find I (current).

Answer 6

so the total resistance is 22

Answer 7

i got .40909

Answer 8

ohh nvm i think i got it it will be 18

Answer 9

is that correct?

Answer 10

No, it should be 2ohm

Answer 11

but its not on the answer choices :/

Answer 12

.409 that must be 1/R
for R you should divide this (1/.409)

Answer 13

well the only 2 in the answer choices is 2.25 and that says 2.44

Answer 14

I got 1/R =0.499
and R =2 ohm

I told you it is not the answer it is the totalt resistance of the circuit.

now we have to use Ohm's law for total current the circuit.

Answer 15

Did you get that ?

Answer 16

ohh ok

Answer 17

yes

Answer 18

so it will be 4.5 ohms

Answer 19

right?

Answer 20

V= IR
I = V/R

Answer 21

amps i mean

Answer 22

yes, exactly ;)

Answer 23

i got it thanks!