Question

How do I expand (2x + y)^6 using Pascal's Triangle?

This is what I got but I haven't used it before so I don't know if I got it right or wrong:

Answer 1

(2x + y) ^ 0 1
(2x + y) ^ 1 2x + y
(2x + y) ^ 2 2x^2 + 3xy + y^2
(2x + y) ^ 3 2x^3 + 5x^2y + 4xy^2 + y^3
(2x + y) ^ 4 2x^4 + 7yx^3 + 9x^2y^2 + 5xy^3 + y^4
(2x + y) ^ 5 2x^5 + 9yx^4 + 16y^2x^2 + 14x^2y^3 + 6xy^4 + y^5
(2x + y) ^ 6

Answer 2

i set it up like this

pascals row
first high to low
last low to high

then multiply down the columns

Answer 3

I haven't even done the last row yet because I think I'm doing it wrong.

Answer 4

use the formula :
(a+b)^n = nC0*(a)^(n-0)*(b)^0 + nC1*(a)^(n-1)*(b)^1 + nC2*(a)^(n-2)*(b)^2 + ... + nCn*(a)^(n-n)*(b)^n

Answer 5

(a+b)^6


1 6 15 20 15 6 1
a^6 a^5 a^4 a^3 a^2 a 1
1 b b^2 b^3 b^4 b^5 b^6