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(z-(1/z))/(1-(1/z)) ill rewright it after I post so it is easier to read
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|dw:1355262097536:dw|
\[\frac{ z-\frac{ 1 }{ z } }{ 1-\frac{ 1 }{ z } }=\frac{ \frac{ z }{ z }-\frac{ 1 }{ z } }{ \frac{ z^2 }{ z }-\frac{ 1 }{ z } }=\frac{ \frac{ z^2-1 }{ z } }{ \frac{ z-1 }{ z } }\]Does this help? There is more to be done...
Typo: the z² in the denominator of the middle term must move up 2 positions ;). In the last term everything is fine..
is the answer z+1?
zehanz
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it is! you 'll get this:\[\frac{ z^2-1 }{ z }*\frac{ z }{ z-1 }=\frac{ z(z-1)(z+1) }{ z(z-1) }\]So only z+1 is left.
Thank you
yw!
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