Question

how to solve this equation?
4x^(1/3)=2x^(-2/3)

Answer 1

could you please use Equation

Answer 2

otherwise it looks messy ` thanks

Answer 3

\[4x^{1/3}=2x^{-2/3}\] it becomes \[2X^{\frac{ 1 }{ 3 }+\frac{ 2 }{ 3 }}=2X^\frac{ 3 }{ 3 }=2x\]

Answer 4

i dont get it ?

Answer 5

hold on

Answer 6

well that 2x=1 and x= 1/2 , just keep the x and its operation on

Answer 7

got it `

Answer 8

thanks `

Answer 9

\[4x^\frac{ 1 }{ 3 }=2x^\frac{ -2 }{ 3 }\] now \[\frac{ 4 x^\frac{ 1 }{ 3 }}{ 2x^\frac{ -2 }{ 3 } }=2x^{\frac{ 1 }{ 3 }+\frac{ 2 }{ 3 }}\]

Answer 10

:D YW