Question

solving quadratics using the quadratic formula
Solve. (x – 5)^2 = 2

Answer 1

You don't need quadratic formula to solve this

Answer 2

but it wants us to use the quadratic formula to solve it @Hero

Answer 3

Just simply take the square root of both sides, then add 5 to both sides. That's all you have to do in order to solve for x. Using the quadratic formula is pointless in this case.

Answer 4

ok thanks @Hero

Answer 5

Solve. x2 = 6x – 6 @hero do you think you can help with this one as well i dont want the answer i just want help

Answer 6

(x – 5)^2 = 2

Square root both sides:
x - 5 = ±sqrt(2)
x = ±sqrt(2) + 5

Answer 7

okay i got it right then thanks now can you help with the second not the answer just help @Hero

Answer 8

x2 = 6x – 6
x^2 - 6x - 6 = 0

In this case, use the quadratic formula:
a = 1, b = -6, c = -6

Answer 9

Quadratic Formula:

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

Answer 10

Plug and play

Answer 11

is the answer \[X=3\pm \sqrt{3}\] @Hero

Answer 12

\[x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4(1)(-6)}}{2(1)}\]

Answer 13

\[x = \frac{6 \pm \sqrt{36 +24}}{2}\]
\[x = \frac{6 \pm \sqrt{60}}{2}\]
\[x = 3 \pm \sqrt{60}\]
\[x = 3 \pm \sqrt{4 \dot\ 15}\]
\[x = 3 \pm \sqrt{4}\sqrt{15}\]
\[x = 3 \pm 2\sqrt{15}\]

Answer 14

what aboutthis one What are the x– and y–intercepts of y = 2x2 – 10x + 8?

Answer 15

@hero sorry for bothering you so much

Answer 16

I'm pretty sure you can figure this one out on your own

Answer 17

yeah i just answered it lol thanks @Hero

Answer 18

To find x intercept, let y = 0 and solve for x.
To find y intercept, let x = 0 and solve for y

Answer 19

yeah thanks :) @Hero