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how to integrate sint^2)
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is it sin(t^2) or sin^2(t)
\[\int\limits_{0}^{x^3} \sin(t^2)dt\]
okay so do you know the anti-derivative of sine?
-cos
correct
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i'm just confused with the t^2 in the inside
well if you where doing the derivative of -cos(t^2) what would you get?
2tsin(t^2) ?
right, but as we see in the integral there isnt a 2t, so therefore we must divide by 2t so cancel this out. Does that make sense?
Have you done integration using substitution?
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yes.
u should make a substitution. u = t^2
then change the dt to du and change the limits and u then should just have to integrate sin u
i origninally thought the antiderivative was \[-\frac{ t^3 }{ 3 } \cos(t^2)\]
shall I show u my method?
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sure.
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