Question

AP CHEM:

Dissociation reaction for each of the following acids in water. Identify the conj. acid-base pairs in each case:

1. C6H5COOH
2. H3BO3
3. H2PO4-
4. HNO3

Whaaaat is this asking. This is on my review sheet & I have a test on this chapter tomorrow ><

Answer 1

Acid means it's gonna lose an H. So C6H5COOH becomes C6H5COO-, which is the conjugate base. That's all you do, remove an H and add a negative charge.

Answer 2

Yeah, I understand that part. I don't get how to write the dissociation reaction. Would that just be Ka = [H+][C6H5COO-] / [C6H5COOH] ? I thought that was the Ka expression...