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a simple integral question
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\[\int\limits_{}^{}\frac{ 1 }{ (x-3)^2 }\]
Do I have to use substitution?
Yes
ah i see
Replace x-3 with u
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u = x-3, du = dx
ah ok ok
thanks zordoloom
Let me know what you get.
yes sir
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uh oh
Take a look at this:
i think i got it
\[-\frac{ 1 }{ x-3 }\]
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Just don't forget the constant.
+c
ok thanks again zordoloom
yes
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