3. What is the sum of a 12-term arithmetic sequence where the last term is 13 and the common difference is -10?
Can you answer my question? This is not a public dating site. -_-
You need the first term of the sequence an = a1 + d(n-1) 13 = a1 - 10(12-1) 13 = a1 - 10(11) 13 = a1 - 110 13+110 = a1 123 = a1 a1 = 123 So the first term is 123
With the first term, the last term and the number of terms, you can figure out what the first 12 terms add to
using this formula S = (n*(a1 + an))/2 S = (12*(123 + 13))/2 ... plug in n = 12, a1 = 123 and an = 13 S = ??
karinewoods17, just ignore POOPSCOOPER153 since he looks like a troll to me
Thank you so much! I didn't know how to find the first term. You are so helpfull. I wish I could give you 1,000,000,000,000... medals:)
you're welcome
no not really, she's just grateful for me actually helping (instead of trolling)
Exactly! Ugh. stupid immature boys.
Is the answer 816?
you got it, the sum of the first 12 terms is 816
Thanks!
yw
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