Question

If a gas has a volume of 1 L at a pressure of 270 kPa, what volume will it have when the pressure is increased to 540 kPa? Assume the temperature and number of particles are constant. Show your work.

Answer 1

P1V1=P2V2

Answer 2

this is a variation of PV=nRT
You are keeping everything on the right side constant, so you can ignore them

Answer 3

really you only need to show that the pressure*volume at first is equal to the pressure*volume after

Answer 4

Can you show me with the numbers

Answer 5

(270)(1)=(540)(x) solve for x

Answer 6

one thing to be careful of when doing these kinds of problems is be aware of your units

Answer 7

how do you solve for x?

Answer 8

divide both sides by 540

Answer 9

0.5=1?

Answer 10

.5=x not 1

Answer 11

So, to show my work itll be:
P1V1=P2V2
270(1)=540(x)
270=540
270 divided by 540 is .5
540 divided 540= 1
so .5 = x

Answer 12

This step doesn't make sense
270(1)=540(x)
270=540
The x doesn't go away

Answer 13

270=540(x)
540 divided by 270=.5
540 divided by 540=1
.5=x

Answer 14

yes that works

Answer 15

Thank you

Answer 16

you're welcome =D