sqrt{-75}
How would I write this in terms of i?

Question

sqrt{-75} 
How would I write this in terms of i?

anonymous · Answer

Simplify the expressions below as much as possible.

Leave no negative numbers under radicals and no radicals in denominators.

anikay · Answer

sqrt(15) right?

anonymous · Answer

I thought so, but the imaginary numbers thing kinda threw me off a little.

anikay · Answer

me too, them tricky problem designers

anonymous · Answer

lol ikr xD Thanks for the help.

anikay · Answer

no prob

raden · Answer

it should be -sqrt(15)

anonymous · Answer

If it were a division problem, how would i work this out? $$\sqrt{-56}\div \sqrt{-7}$$

anonymous · Answer

why would it be negative sqrt?

raden · Answer

first, u have to remember defined that sqrt(-1) = i
sqrt(-3) = sqrt(-1) *sqrt(3) = i sqrt(3)
sqrt(-5) = sqrt(-1) *sqrt(5) = i sqrt(5),
so sqrt(-3)*sqrt(-5) = i sqrt(3) * i sqrt(5) = (i)^2 sqrt(15) =
(sqrt(-1))^2 sqrt(15) = -sqrt(15)

anonymous · Answer

Thank you.

raden · Answer

do same idea for the 2nd ....
welcome ^^

anonymous · Answer

please help me with this question State http://openstudy.com/study#/updates/50c7fe7de4b0a14e43688878

anonymous · Answer

since $-75=25\times3\times (-1)$ you have 
$$\sqrt{-75}=\sqrt{25}\times \sqrt{3}\times \sqrt{-1}=5\sqrt{3}i$$