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calculate the integral: equation below
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\[\int\limits_{0}^{\pi}sinxdx\] the top one is pi
Do you know how to integrate sinx ?
i knowed,:P
itd be cosx
wrong, it should be -cosx
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2
oh because derivative of sinx=cosx and cox=-sinx so anti derivateve would be -cosx and the answer would be 2
its -cos x. So you substitute the upper limit minus the bottom limit into the integrated function. -cos pi - (-cos 0)
Yes
ok thanks.
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