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An advertising balloon has radius 6m. Air leak out at a rate of 28 pi m^3/minute. Find the rate of decrease of the diameter after 9 minute ?
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what is the volume of a sphere in term of the radius?
oh i think it is \[V=\frac{4}{3}\pi r^3\]
taking derivatives you get \[V'=4\pi r^2 r'\] you are told \(V'=28\) solve for \(r'\)
ohh
how about 9 min ?
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i made an equation like this: 28= 4/3π3r dr/dt
i mean r^2
yes, and you can find \(r\) because you know that initially it was 6 m and you know the rate of decrease
thank you :)
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