Question

Find the number of grams of oxygen that will be needed to burn 1.06 moles of methane, CH4 to produce carbon dioxide and water

Answer 1

1) Balance the equation:
CH4 + 2O2 --> CO2 + 2H20
2) mol --> mol --> grams
(1.06 mol CH4)(2 mol O2/ 1 mol CH4)(32.00 g O2 / 1 mol O2) = 67.8g O2

Answer 2

67.84 g of O2 requires to burn 1.06 moles of methane