Question

how do you go from slope intercept form to standard form

Answer 1

slope-intercept form is :

y = mx + b

Since the standard form is ax + by = c you just bring the mx term over to the left:

-mx + y = b

and now you are in standard form

Answer 2

can youexplain what you wrote in this examples
6y=18x-12
2y=8-6x

Answer 3

@tcarroll010 @tcarroll010 @tcarroll010
can youexplain what you wrote in this examples
6y=18x-12
2y=8-6x 2

Answer 4

slope-intercept form: 6y =18x - 12
standard form: -18x + 6y = -12
can also be written: 18x - 6y = 12

Answer 5

but can you explain how you got that @tcarroll010 @tcarroll010 @tcarroll010

Answer 6

I already did.

Answer 7

like each step no you didnt can you just explain again please

Answer 8

@tcarroll010

Answer 9

There's nothing more I can add to my explanation. I moved the "mx" term from the right-hand side over to the left-hand side. The technique is by subtracting that "mx" term from both sides and preserves the equality. In general:

If a = b + c and you want to get "c" over to the left, you subtract it from both sides.

a - c = (b + c) - c -> a - c = b + (c - c) -> a - c = b + 0

a - c = b

And that's all there is to it.