Question

(1-cos^2x)(cscx)

Answer 1

You do know that \(\sin^{2}(x) = 1 - \cos^{2}(x)\)?

Answer 2

no

Answer 3

Are you sure? Maybe \(\sin^{2}(x) + \cos^{2}(x) = 1\) looks more familiar?

Answer 4

is that what you think the answer is?

Answer 5

It's called a hint.

Answer 6

well can you explain step by step how to so it.

Answer 7

*do

Answer 8

I did, already, in my first post. Take a good, hard look at that and ponder your original expression.

Answer 9

try replacing cscx with its reciprocal.... then multiply....

Answer 10

answer is\[\sin x\] You know csc x = 1/sinx, and cos^2x+sin^2x = 1. So 1-cos^2x = sin^x, and sin^2x*cscx = sin x

Answer 11

NOTE:
\[\csc(x) = \frac{ 1 }{ \sin(x) }\]
Similarly,
\[\cot(x) = \frac{ \cos(x) }{ \sin(x) }\]
\[\tan(x) = \frac{ \sin(x) }{ \cos(x) }\]
\[\sec(x) = \frac{ \ 1 }{ \cos(x) }\]
\[1-\cos^2(x) = \sin^2(x) \]