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Convert the polar representation of this complex number into its rectangular form: z=7(cos(pi/2)+ i sin(pi/2)) A. (0,-7) B. (0,7) C. (7sqrt(3), 0) D. (-7,0)
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B. (0,7)
why is that correct?
@hartnn
as cos(pi/2) =0 and sin(pi/2)=1 for (x,y) correspond to some form of a+ib
@hartnn
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pi/2 is the standard angle, you must remember its cos and sin values. then its just the matter of substitution.
the i is messing with me here... lil help?
in co-ordinates a+bi can be represented as (a,b) so, 0+7i will be represented as (0,7).
so... that was right?
yup.
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