Simplifying radical expressions

Question

anonymous · Answer

attachment

anonymous · Answer

give me the prime factorization of 56....
56 =

anonymous · Answer

ok. hang on

anonymous · Answer

56=2*2*2*7?

anonymous · Answer

good... ur getting the hang of this....

anonymous · Answer

how many triple factors of 2,
how many triple factors of 7, 
how many left over of each?

anonymous · Answer

1 triple factors or 2 and 0 of 7 and thers a 7 left over..and thankyou..you have done a good job explaining it. i appreciate it a lot, im not very good at math

anonymous · Answer

seems u r good in math.... give urself more credit... :)

anonymous · Answer

how many triple factors of x's  in    $\large x^{14} $  ????

anonymous · Answer

aw, well thanks! lol. and 4 triple factors?

anonymous · Answer

yes... and how many left over?

anonymous · Answer

2

anonymous · Answer

ok... so we'll put all this together now...

anonymous · Answer

$ \large \sqrt[3]{56x^{14}}=\sqrt[3]{56} \sqrt[3]{x^{14}}=2\sqrt[3]{7}\cdot x^{4} \sqrt[3]{x^2}=2x^4 \sqrt[3]{7x^2}$

anonymous · Answer

goodness thats long. thankyou.. im going to try to do this last one on my own....ill see if I can do it.

anonymous · Answer

sure... just page if u need help...

anonymous · Answer

alright, i honestly might need help because i have to make up my own radical expression

anonymous · Answer

np...

anonymous · Answer

I posted it in a new one