Question

help

Answer 1

i think A.

Answer 2

\[\Large \frac{\frac{x^2+2x+1}{x-2}}{\frac{x^2-1}{x^2-4}}\]

is the same as

\[\Large \frac{x^2+2x+1}{x-2} \times \frac{x^2-4}{x^2-1}\]

Answer 3

and you can combine the fractions to get

\[\Large \frac{(x^2+2x+1)(x^2-4)}{(x-2)(x^2-1)}\]

Answer 4

then factor everything to get

\[\Large \frac{(x+1)(x+1)(x-2)(x+2)}{(x-2)(x-1)(x+1)}\]

Answer 5

so what would the answer be ?

Answer 6

A is correct lol.

Answer 7

yes, cancelling the common factors leads to

\[\Large \frac{(x+1)(x+2)}{x-1}\]

which is A