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Find dy/dx. y=5^(ln(x^2)+3)
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\[a^x \ln(a)\]
thank you!:)
fa sho! GL!
lol, the clue incomplete... use chain rule : y=x^2 ---> y'=2x v=ln(u) ---> v'=1/u w=5^v ---> w'=5^v * ln(5)
ok, i got this.. y'= 5^(ln((x^2)+3)) *ln 5*((2x)/((x^2)+3)) ..is it right?
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for the power of 5, is {ln(x^2) + 3} or ln(x^2+3)
i did include that, im just not sure if i did it right?, do i have to put (1/5) for ln5?
before verify, i want to asking u is ur question |dw:1355302758870:dw|
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