Question

64-m^2

Answer 1

Use \(a^2-b^2 = (a+b)(a-b)\)

Answer 2

which one would be A in this case

Answer 3

64 - m^2
= 8^2 - m^2 ... Compare with
a^2 - b^2
What do you think?

Answer 4

im stuck at (8+m) (8-m)

Answer 5

Done :|
If you mean factorizing the polynomial..

Answer 6

well the directions say factor the polynomial completely. if the polynomial cannot be factored, write "prime"

Answer 7

Then, that's it.

Answer 8

so the next one was X^2 + 25....for this one i got (X+5) (X-5)

Answer 9

i dont think that correct

Answer 10

Indeed, that is not correct!

Answer 11

When you expand (x+5) (x-5), you won't get x^2+25

Answer 12

would they both be (x+5)

Answer 13

Nope...
(x+5)(x+5)= x(x+5) + 5(x+5) = ... =/= x^2+25

Answer 14

do you know where im going wrong

Answer 15

Hmm...
When you see a^2-b^2, it can be factorized, but a^b+b^2 cannot, at least not for the case when it has only real factors.

Answer 16

so x^2+25 cannot be factored

Answer 17

Yes!

Answer 18

so thats one is finished

Answer 19

Yes~

Answer 20

thanks...should i open a new question box or could i stay in this one