Question

Find the relative extrema:
f(x) = x^4+4x^3

Answer 1

\[f'(x)=4x^3+12x^2\]
\[4x^2(x+3)\]
\[x=0,-3\]

Answer 2

yeah thats what i got:\

Answer 3

but at the back the answer is only:
Rel. Min(-3,-27)

Answer 4

hmmm

Answer 5

have you try to plug in -3 into original equation/

Answer 6

would that be a mistake my teacher made

Answer 7

if you plug in -3 into original equation you should get -27

Answer 8

I got -189 for some reason...

Answer 9

@winterfez

Answer 10

\[(-3)^4+4(-3)^3\]

Answer 11

use BRACKET for -3

Answer 12

OHHH

Answer 13

IN'T THAT REL. MAX THOUGH? not rel. min

Answer 14

oops sorry for CAPS xD

Answer 15

is (-3,-27) the Relative Max not Relative Min?

Answer 16

and the Relative min. would be 0 rite?

Answer 17

It not really specify if they want an interval or not

Answer 18

-27 is relative min at poin -3 and 0 is max at point 0

Answer 19

oh wait nvm

Answer 20

thank you :)

Answer 21

or you could say -27 is relative min at x=-3...0 is max at x=0

Answer 22

YW