The management of a store wishes to add a fenced in rectangular storage yard of 20,000 sq.ft. using the building as one side of the yard. Find the minimum amount of fencig that must be used to enclose the reamining 3 sides of the yard. Find the dimensions
the answer at the back was w=100' and l=200'
so far i did \[20,000=2x+y\] \[y=20,000-2x\] then i plugged that into \[A=x \times y\] \[A= x(20,000-2x)\] \[A=20,000 - 2x ^{2}\] then I got the derivative of that \[A'= 20,000 - 4x\] then I got \[x=5,000'\] Then I plugged that into \[y=20,000 - 2x\] and I got \[y=10,000'\]
is the other way aroud you hav 20,000 SQUARE feet...what do you think of?
so i squred 20,000?
lol
oh A=20,000
so how would I do this problem :\
well you think of area because is a SQUARE thus A=>xy=20000
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take derivative of perimenter and solve for x
\[P'=2 + \frac{ 20000 }{ x^2}\] is this the derivative of the perimeter? xD
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ok then what o:
solve for x
how can i get \[x^2\] by itself here
\[\frac{ -20000 }{ x^2 }=-2\] \[-20000=-2x^2\] \[10000=x^2\] \[x=\sqrt{10000})\]
\[A-->y=\frac{ 20000 }{ \sqrt{10000} }\]
okay thank you <333
yw
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