I need help *** if someone can get back to me you will get a medal!! really need help lost
Post the question you need help with, and not an advertisement to "swap answers" please
what quiz
ok for the function 32 over x+3 find (g^-1*g(5)
Graphing Radical Functions Quiz '
what is the value of g(5)?
Sorry it soupposed to be (g^-1*g)(5)
I dont remeber that, srry I take Geometry and Id ont rmeber how to solve
it does not say what g equals
im pretty sure g is the name of the function they gave you
\[g(x)=\frac{32}{x+3}\]
ok so i multiply that funtion by itself to the -1 power?
the -1 notation here denotes the inverse of the function .. not really a power
do you know how to find an inverse?
not really
given a function \[y=\frac{32}{x+3}\] the inverse swapps x and y, so the inverse of this is \[x=\frac{32}{y+3}\]
so now i divide?
lets work the inverse a little more .. just so things loook normal \[x=\frac{32}{y+3}\] \[y+3=\frac{32}{x}\] \[y=\frac{32}{x}-3=g^{-1}(x)\]
so, \[g^{-1}*g=(\frac{32}x-3)(\frac{32}{x+3})\] plug in x=5 and find the product
4
now what? would i times 4 by 5?
not if your following what ive written ....
the answer choices are 11 5 2 and 1 so ???
what now
sorry i am not good at this
hmm, you sure thats a "*" in between them or is it more of an "\(^o\)"
an o
ahhh, that changes things, the open "o" means a composite, not a multiplication of the 2 of them
g^(-1) o g has a property that the input is the same as the output
could you check out the math chat box it may need to be controlled.
it needs the adminstrators to come online and deal with the isp itself .. so that the whole school gets banned
so if the input is 5, what is the output?
5?
-5
yes, if the input is 5, the output is 5 ... its a special property of composing inverses of each other
what school. Cant you bn them if they need
so if there is an o don't multiply make input sam as output?
only if the functions are inverses of each other does that work. If they are not inverses the input and output can be different
brb domestic situation at house have to help brother
good luck ::)
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