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Mathematics 16 Online
OpenStudy (anonymous):

In the Half Angle ID how do you know whether to use the + or - sign?

hartnn (hartnn):

ID ?

OpenStudy (anonymous):

anyone :c

Parth (parthkohli):

identity.

Parth (parthkohli):

Both signs.

hartnn (hartnn):

half angle identity of what ?

Parth (parthkohli):

\(\pm\) is just one addition that something applies to both signs.

OpenStudy (anonymous):

yea but youd have to chose wether its - or +

Parth (parthkohli):

You have to choose both. See, it's actually the point that a square root can be both positive and negative.

Parth (parthkohli):

For example, the square root of 64 is \(\textbf{both}\) 8 and -8. If you're lazy, then you say that it is \(\pm 8\). Get the point?

hartnn (hartnn):

where did half angle come in this picture ?

Parth (parthkohli):

sin(x/2) and cos(x/2) @hartnn

OpenStudy (anonymous):

Okay so like if you were to solve Cos (13pi/12 )

OpenStudy (anonymous):

how do you know it simplifies to -\[-\sqrt{1+\cos (13\Pi/6)}/2\]

OpenStudy (anonymous):

Like how do you decide theres a (-)

hartnn (hartnn):

depending on the quadrant in which the angle lies.

hartnn (hartnn):

13 pi/12 lies in which quadrant ?

OpenStudy (anonymous):

1?

OpenStudy (anonymous):

Because you have to mult by 1/2

hartnn (hartnn):

13pi/12 = pi + pi/12 , right ?

OpenStudy (anonymous):

you mean 1/2 times pi/ 13 ... Like thats how to simplify it

OpenStudy (anonymous):

oops i mennt 1/2 times 13pi/6

hartnn (hartnn):

before doing 1/2 times..... whatever, u need to find where your original angle lies., in which quadrant.

OpenStudy (anonymous):

oh

hartnn (hartnn):

13pi/12 = pi+pi/12 lies in which quadrant ?

hartnn (hartnn):

hint : 1st Quad : 0 to pi/2 2nd Quad : pi/2 to pi 3rd Quad : pi to 3pi/2

OpenStudy (anonymous):

if would be Q2 but like how does 13pi/12 = pi+pi/12

hartnn (hartnn):

pi + some angle will go beyond 2nd Quadrant so its in 3rd Quadrant, ok ?

OpenStudy (anonymous):

Oh okay

OpenStudy (anonymous):

but still dont get how you did 13pi/12 = pi+pi/12

hartnn (hartnn):

that is simple arithmetaic, since, 13pi/12 was greater than pi, i subtracted pi. and got pi/12 so, 13pi/12 = pi+pi/12

hartnn (hartnn):

and in 3rd Quadrant, cosine is negative... hence, you select, - **minus**

OpenStudy (anonymous):

Lol okayyes can you give me another problem so I can practice how to find with Q its in

hartnn (hartnn):

yes, 13pi/7 which Quad ?

OpenStudy (anonymous):

wuld it also be in Q 3...

hartnn (hartnn):

nopes, how Q 3 ?

OpenStudy (anonymous):

I thought of it like pi + pi/7

hartnn (hartnn):

can you convert radians into degrees ?

OpenStudy (anonymous):

man hhow come I dont understand how to do it x_x

OpenStudy (anonymous):

oh yes

hartnn (hartnn):

i will give a better method, can you convert radians into degrees ? then convert and tell me what u get.

OpenStudy (anonymous):

Wait would it be in the Q2

hartnn (hartnn):

no.

hartnn (hartnn):

13pi/7 = 13*180/7 = 334.28...now 334 is in which Q ?

hartnn (hartnn):

its less than 360 and > 270

OpenStudy (anonymous):

the 4th ._.

hartnn (hartnn):

yup. so convert the angle into degrees and then its easy...

hartnn (hartnn):

one more ?

hartnn (hartnn):

7pi/6 ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

okay so I would use the method part / whole

OpenStudy (anonymous):

so 7pi/6 / 2pi = x / 360

hartnn (hartnn):

? pi radians = 180 degrees 7*180/6 =210 210 in which Quadrant ?

OpenStudy (anonymous):

I got the Q3

hartnn (hartnn):

yes. got it how to find which Q ?

OpenStudy (anonymous):

wait one more lol

hartnn (hartnn):

ok, 3pi/4

OpenStudy (anonymous):

lol I alreadyady know that one its in Q2

hartnn (hartnn):

lol then pi/12

OpenStudy (anonymous):

Q1

hartnn (hartnn):

yes, last 5pi/3

OpenStudy (anonymous):

oh srry I am also doing my essay lol but um okay for thisone it will beeee

OpenStudy (anonymous):

um so it would be in Q2

hartnn (hartnn):

no, try again.

OpenStudy (anonymous):

WAIT I MEANT Q$

OpenStudy (anonymous):

*Q4

hartnn (hartnn):

excellent! now i award you Masters Degree in finding Quadrant of an angle. :P you can continue with your essay....

OpenStudy (anonymous):

lol thnkx btu I have more math questions.. I hve a test today x_x

hartnn (hartnn):

\[ \begin{array}l\color{red}{\text{w}}\color{orange}{\text{e}}\color{#e6e600}{\text{l}}\color{green}{\text{c}}\color{blue}{\text{o}}\color{purple}{\text{m}}\color{purple}{\text{e}}\color{red}{\text{ }}\color{orange}{\text{^}}\color{#e6e600}{\text{_}}\color{green}{\text{^}}\color{blue}{\text{}}\end{array} \] sure, do ask...

OpenStudy (anonymous):

okay I'll make new questions

hartnn (hartnn):

:)

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