Question

What is the center for the circle below(see attachment) then find the equation of the circle.

Answer 1

-3,5

Answer 2

ok so can you put this equation into standard form? x^2+y^2+6x-10y+9=0

Answer 3

uuuuuuuuhhhhhhh nope

Answer 4

ok thx anyways

Answer 5

NP try googling it

Answer 6

@RadEn can you help me? i need to put this equation x^2+y^2+6x-10y+9=0 into standard form

Answer 7

do you know how to complete the square?

Answer 8

umm what do you mean @dpaInc ?

Answer 9

so i have put x's and y's togethe rand i got x^2 + 6x + y^2 - 10y + 9 = 0

Answer 10

would this be correct? (x^2 + 6x + 3^2) + (y^2 - 10y + 5^2) 9 = 3^2 + 5^2

Answer 11

so i tried to solve the above equation and i got (x - 3)^2 + (y + 5)^2 = 43 would this be correct?

Answer 12

are you there? @dpaInc

Answer 13

so would this be the answer (x + 3)^2 + (y - 5)^2 - 25 = 0?

Answer 14

you can leave it as (x + 3)^2 + (y - 5)^2 = 25
because this is called center-radius form for the equation of a circle...