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help? step by step? (: limit as x approaches 0 of (1-cos(x))/(x^2)
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l'hopital will work nicely first check that if you replace \(x\) by 0 you get \(\frac{0}{0}\) which you do
then take the derivative top and bottom, bet \[\frac{-\sin(x)}{2x}\] which, if you replace \(x\) by \(0\) still gives \(\frac{0}{0}\) so it is l'hopital again
this time the derivative gives you \[\frac{-\cos(x)}{2}\] and now replacing \(x\) by \(0\) gives the limit as \(-2\)
It's actually 1/2 (:
yeah, that one!
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lol (; I got the point though.
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