Find the slope of the graph of the function at F(x) =4/x^2 when x=5
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OpenStudy (anonymous):
f(5)=4/5^2=5/25
OpenStudy (anonymous):
Oh, that's all? Thanks so much!
OpenStudy (anonymous):
But I need to find f'(5), not just f(5)
OpenStudy (anonymous):
F(x) =4/x^2
y =4/x^2
to find the inverse you need to change the x and y then solve for y
x = 4/y^2
y^2*x=4
y^2=4/x
sqrt(y^2)=sqrt(4)/sqrt(x)
y = 2/sqrt(x) = 2sqrt(x)/x
OpenStudy (anonymous):
2*sqrt(5)/5
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OpenStudy (anonymous):
does that look right?
OpenStudy (anonymous):
errr, I don't think so, sorry : /
These are my answer choices:
A. -8/5
B. 8/125
C. 8/5
D. -8/125