Question

plz help

Answer 1

\[\frac{ cscx ^{2} +2cscx-3}{ \csc ^{2}x-1 }=\frac{ cscx+3 }{ cscx+1 }\]

Answer 2

@zepdrix

Answer 3

@ChmE

Answer 4

http://www.sosmath.com/trig/Trig5/trig5/trig5.html

Answer 5

that is confusing. K so for the first step i did (csc^2x+1)

Answer 6

multiplied that to top and bottom

Answer 7

I'm more concerned about how to simplify the right side. I don't see it at first glance, which tells me that we might not have to. **We can factor the numerator** picture cscx is just x.

Answer 8

k so do right first and mul deno and numoretor by csc-1

Answer 9

\[\frac{ (\csc x -1)(\csc x +3)}{ \csc ^{2}x-1 }=\frac{ cscx+3 }{ cscx+1 }\]

Answer 10

lets factor the denominator too :) !!!

Answer 11

\[\frac{ (\csc x -1)(\csc x +3)}{ (\csc x-1)(\csc x +1) }=\frac{ cscx+3 }{ cscx+1 }\]We can cancel and we are done

Answer 12

omg it was thateasy ijust looked at the wrong side i guess. thanks

Answer 13

yw